A calculus of definitions, with normalisation as evaluation ------------------------- We present a small calculus with constructors and functions defined by pattern-matching. The difficulty is to do computations on open terms and to give the result in the expected form. Example: f 0 = 0, f (S x) = f x We may want to evaluate f (S (S X)), X variable. The expected form for the result is f X. We give a simple way to implement this language, using the idea of normalisation as evaluation. We describe a notion of values for the language, and the normal form of an expression will be its semantics. More example: we want to be able to define (all definitions are recursive) f 0 = 0 f (S n) = g n g 0 = S 0 g (S n) = f n h 0 = g (f 0) h (S n) = g (h n) and then to evaluate symbolically, for instance h (S (S x)) the result should be g (g (h x)) We want also to have definitions inside a definition. For instance f x = let h 0 = x h (S n) = f (h n) in h x If we evaluate symbolically f (S y), the result will be f ((f y).h y) If we rewrite this naively we get f (h y). Notice that the name h is local to the function f. We represent this by writing (f y).h instead of h. We indicate that this is the function h, which occurs in the definition of f, with the argument y. 1. Basic language -------------- Language: syntax of terms M ::= x | M M | \x M | c M1 ... Mk The name x can be a variable bound by an abstraction, or by a definition. The definitions are E ::= \ x E | D E | H H ::= M | F F ::= D ::= x1=E1,...,xn=En The definitions are recursive. V ::= Lam f | N | c V1 ... Vk N ::= P | N V | P N P ::= () | P.x | P V We define [M]r as usual. [x]r = r(x) [M1 M2]r = [M1]r ([M2]r) [\x M]r = Lam f where f V = [M](r,x=V) The crucial point is the computation of [D](P,r) [D](P,r) is x1 = V1,...,xn = Vn where Vi = [Ei](P.xi,r') with r' = r,x1=V1,...,xn=Vn [\x E](P,r) = Lam f where f V = [E](P V,(r,x=V)) [D E] (P,r) = [E](P,r') where r' = r + [D](P,r) [M](P,r) = [M]r [](P,r) = Lam f where f (ci w) = [Ei](P,r) w f V = P V if V is not of the form ci w 2. Addition of infinite objects ----------------------------- To see how we can represent infinite objects, we can add records (that may be infinite) M ::= x | M M | \x M | c M1 ... Mk | M.x E ::= \ x E | D E | H H ::= M | F | R R ::= (x1=M1,...,xn=Mn) The new values are V ::= Lam f | N | c V1 ... Vk | (P,W) N ::= P | N V | P N | N.x P ::= () | P.x | P V W ::= (x1 = V1,...,xn=Vn) We have added "infinite values" (P,W) that have two components. If R = (x1=M1,...,xn=Mn) we define [R](P,r) as (P,(x1 = [M1]r,...,xn = [Mn]r)) Examples: f = (u = f,v = 0) This is an infinite object. If we compute [f] we get (f,(u=[f],v=0)) If we compute [f.u] we get the same as [f] and if we compute [f.v] we get 0. Another example is f = \ x (u = f 0,v = f (f x)) We can then form f (S 0) the value is [f (S 0)] = (f (S 0),V) where V = (u = [f 0],v = [f (f (S 0))]) Thus if we take (f (S 0)).u we get something of the form (f 0,...). 3. Package ------- We can package the definitions arbitrarily, with parameters. This is actually definable as soon as we have records. p = \ x1...\ xk D1...Dn (y1 = y1,...,ym = ym) where y1,...,ym are the definitions among D1,...,Dn that we want to make accessible for outside. For instance p = \ x let w = (u = x,v = f 0) f 0 = x f (S n) = (u = f n,v = w) in (w=w,f = f) We can then consider (p 0).f (S 0) which has for values (p 0).f (S 0), (u = 0,v = (p 0).w) Thus if we compute ((p 0).f (S 0)).v we get (p 0).w